Jump to content

greatest common divisor


Recommended Posts

Hello, I have problem with finding every possible number value of [latex]GCD(a^2b+b^2c+c^2a, ab^2+bc^2+ca^2, a+b+c)[/latex] where assumptions are:
[latex]a,b,c[/latex] are three different integer number, [latex]GCD(a, b, c)=1[/latex] and [latex]a,b,c > 1[/latex].

 

I tried first find the [latex]GCD(a^2b+b^2c+c^2a, ab^2+bc^2+ca^2)[/latex] and next [latex] GCD(GCD(a^2b+b^2c+c^2a, ab^2+bc^2+ca^2), a+b+c)[/latex] by euclidean algorithm but it wasn't work for me, also i don't know how to use the assumption [latex]GCD(a, b, c)=1[/latex]

I checked a couple examples in wolframalpha and it always return 1 so I guess it is the answer but I can't prove it.

Edited by johnmayer18
Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.