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Question: How many grams of sodium oxide are produced when 73.2g of sodium react completely with oxygen gas?

 

Just want to confirm if my procedure/answer is correct.

 

4 Na + O2 ---> 2 Na2O ----- Balanced Equation

So I would assume all I have to do is 1) get the moles of Na 2) divide my 2 to get the moles of Na2O 3) multiply by the molar mass of Na2O to get the grams of Na2O.

Solution:

73g ÷ 23g/mol (molar mass Na) = 3.2 moles

3.2 moles ÷ 2 = 1.6 moles of Na2O

1.6 moles × 62 g/mol (molar mass of Na2O) = 98.7

 

Did I do my computations correctly?

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