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Hydrogenation of 1-Octene to n-Octene


nemzy

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1) how many moles of h2 gas should be taken up by 1 octene in the courseof this reaction?

 

 

CH3-(CH2)5-CH=CH2 -> (H2PtCl6) -> NaBH4, C2H5OH, HCL -> CH3-(CH2)5-CH2-CH3

 

Answer is 2 right???

 

2) What volume does this correspond to at STP?

 

How can i solve this part?

 

 

3) how many moles of molecular hydrogen are consumed per mole of the precatalyst (H2PtCl6) in order to convert it enterily to platinum metal?

 

Isnt this 2 also?? what is the diff between this and the moles of H2 gas for the question #1?

 

4) How many moles of precataylst (H2PtCl6) are used in this reaction?

 

Again is isn't this 2??

 

My answers don't seem right and i am still a little dubios before submitting them...am i misunderstanding a simple concept here?

 

thanks

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