Jump to content

Eigenvectors of 3*3 matrix

Featured Replies

Hi guys,

 

I am struggling with finding eigenvectors of a 3x3 matrix in a change of coordinates problem. Basically,
I have taken the equation x^2 - z^2 - 4xy +4yz, converted it into matrix [1 -2 0; -2 0 2; 0 2 1] and found the eigenvalues

 

 

1

1/2 + sqrt(33)/2
1/2 - sqrt(33)/2

But I am truly struggling with the eigenvectors here. The first one (l=1) is easy, but the other ones not. I plug the eigenvalues in the matrix and using Gauss-Jordan, I only get 1's on the diagonal. But I cannot determine such a vector, as I would think that it is [x1 x2 x3] = [0 0 0].

 

Help?

The zero vector 0 is -in some sense- an Eigenvector to every matrix A and every eigenvalue n, since A0 = 0 = n0. From the little you said (in detail) about how you try to determine the eigenvector, I have the gut feeling you don't really know what you are doing. Take the eigenvalue 1: When looking to an eigenvector to this eigenvalue, what you are looking for are all possible solutions [math]\vec x[/math] to the system of equations [math]A\vec x = 1 \vec x[/math].

Archived

This topic is now archived and is closed to further replies.

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.