Jump to content

Deriving the equation of points for exact fitting and shape analysis

Featured Replies

I would like to ask you some questions.

 

1) I've a closed curve (for example an ellipse, which may represent the contour of an object) represented by the set of its (known) points. I need to find the equation of that curve to pass through all and every point (exact fit). I think that to do this I need a polynomial whose grade is equal to the number of points less 1.

 

Something like this:

 

a0+a1 x1+a2 x1^2+ ...+ an x1^n = y1

a0+a2 x2+a2 x2^2+ ...+ an x2^n = y2

...

a0+a2 xn+a2 xn^2+ ...+ an xn^n = yn

 

This argument is right? Do you have suggestions (or anything else relevant) for me in this regard for which is the best way to solve my problem? This equation can be made in parametric form?

 

2) After I got the exact equation of this curve. Suppose we have a set of curves very similar to each other (represented by their equation), I would like to find the equation that represents the shape which best approaches to all previous curves, a sort of average curve created from those previously acquired.

Do you know if this thing can be done and how? What is the best way (most efficient and / or mathematically more correct) to do this?

 

Best Regards,

 

Giusy

Archived

This topic is now archived and is closed to further replies.

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.