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Inertia of Meter Stick

RVJ
in Homework Help

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So I'm currently working on some physics homework to prepare for an upcoming exam. We were assigned the following problem:

 

"Calculate the rotational inertia of a meter stick, with mass 0.56kg, about an axis perpendicular to the stick and located at the 20cm mark. (Treat the stick as a thin rod.)"

 

Here is how I attempted to solve the problem:

 

Using the Parallel-Axis Theorem,

I=Icom + Mh2

I found the Icom (using a table of values) to be:

(1/12)ML2

Filling it in for the equation:

I=(1/12)ML2 + Mh2

Knowing the values of every variable, I plugged in:

I=(1/12)(.56kg)(1)2 + (.56)(.3)2

 

My final answer was:

I=.097 kg-m2

But using the list of answers our Professor provided, it's supposed to be .97 kg-m2. I'm inclined to think the professor made a typo?

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