Does it matter if a bosun meets an anti-bosun?

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Does it matter if a bosun meets an anti-bosun?

 

Of all the 'regular' bosons only the W boson has an 'anti-particle. The W- and W+ are anti-particles. The rest, like the photon, are their own anti-Particle.W bosons can decay to a lepton and neutrino or to an up-type quark and a down-type quark. The decay width of the W boson to aquark–antiquark pair is proportional to the corresponding squared CKM matrix element and the number of quark colours, N_C = 3. The decay widths for the W bosons are then proportional to:LeptonsUp quarksCharm quarkse+ν

e1ud3|V_ud|²cd3|V_cd|²μ+ν

μ1us3|V_us|²cs3|V_cs|²τ+ν

τ1ub3|V_ub|²cb3|V_cb|²Here, e+, μ+, τ+ denote the three flavours of leptons (more exactly, the positive charged antileptons). ν

 

 

e, νμ, ντ denote the three flavoursof neutrinos. The other particles, starting with u and d, all denote quarks and antiquarks (factor N_C is applied). The various V_ij denote the corresponding CKM matrix coefficients.

 

Unitarity of the CKM matrix implies that |V_ud|² + |V_us|² + |V_ub|² = |V_cd|² + |V_cs|² + |V_cb|² = 1. Therefore the leptonic branching ratios of the W boson are approximately B(e+ν

 

 

e) = B(μ+νμ) = B(τ+ντ) = ¹⁄₉. The hadronic branching ratio is dominated by the CKM-favored udand cs final states. The sum of the hadronic branching ratios has been measured experimentally to be 67.60±0.27%, withB(l⁺ν_l) = 10.80±0.09%.^[9]

 

 

 

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