Lois.Cypher Posted August 14, 2012 Share Posted August 14, 2012 ∫(1+tanx)/(1-tanx) the answer is supposed to be -log| cosx - sinx | + C, but I just can't seem to get there. Can someone please tell me the steps to get there? Link to comment Share on other sites More sharing options...
ajb Posted August 14, 2012 Share Posted August 14, 2012 (edited) What have you got so far? One hint is to simplify [math]\frac{1+ \tan(x)}{1-\tan(x)}[/math] by multiplying and dividing by [math]\cos(x)[/math]. Do this and then see if you notice anything about the numerator and the denominator. Edited August 14, 2012 by ajb Link to comment Share on other sites More sharing options...
Lois.Cypher Posted August 14, 2012 Author Share Posted August 14, 2012 @ajb Ahh thanks a lot, I understand now. Link to comment Share on other sites More sharing options...
ajb Posted August 14, 2012 Share Posted August 14, 2012 Ahh thanks a lot, I understand now. Great. I am glad to have helped. Link to comment Share on other sites More sharing options...
abvegto Posted August 14, 2012 Share Posted August 14, 2012 take tanx = sinx / cosx ...then simplify then rationalize Link to comment Share on other sites More sharing options...
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