A gas X

 

is 42g/mol

 

 

A gas Y

 

is 56g/mol

 

 

If both gas are in mixture, the mixture is 42g/mol

 

 

which gas in that mixture is more abundant??? X or Y??

 

Can any one explain to me in details as well??

 

thx

 

Albert

gas X, as any introduction of gas Y would increase the value.

 

there`s no mix, it`s a trick question

I know they dont actually chemically "mix" together.....

 

Can you give me a bit of chemical and mathematical manipulation??

 

Albert

Sorry, for duplicating post...

 

but could any one help me?? I am stuck on this....

 

thx in advance !!

x=42 y=56

 

the "Mix" can`t be if they are the only 2 gasses. 42 is the least it can be if only X is used, ANY introduction of Y would take that value higher!

 

it would be different if there were a 3`rd gas lower than 42 or gas X was lower than 42, but there isn`t.

 

there`s no mix!

Ohhhhhhh

 

so.... when the two gases are placed together, their g/mol is 42 in average right??

 

In average, both sides need to offer 42g....., the higher g/mol must give less amount of moles

 

but this question is not actually correct to me. There is 4/7 of gas X and 3/7 of gas Y, according to my calculation...., and if 4/7 is 1 mol, then 3/7 should be less....., then when we divide 84g (the total mass) by the amount of the total mols, the result couldn't be 42g/mol

 

Any help?

 

Albert

when the 2 gasses are mixed its (42+56)/2 to give the G/Mol.

 

and that`s 49 g/mol.

 

any introduction af gas Y to gas X will always be higher than 42, no matter how small an amount.

In a equation, for two different types of composition,

Let z% be the composition of x and (100-z)% be the composition of y.

The new weight=[xz+y(100-z)]/100

So, YT, do you mean that there is even none of gas Y in the so-called mixture??

 

Albert

that`s exactly what I mean.

 

based upon the parameters in your original post yes