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Question about the imaginary number

Ambition On Acid
in Mathematics

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I have just a simple question about the imaginary number i : Since it's the square root of -1, is -i2 equal to 1?

 

Thanks smile.gif

 

Yup! That is if you meant [math]-(i^2)[/math] (which is what your notation would imply :D

[math](-i)^2[/math] is also -1

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