I have been trying to balance this equation... I have balanced all the elements on both sides of the equations besides H's and O's and once I balanced the H's, I can't seem to balance the O's to make the whole equation equal! Step-by-step would be greatly appreciated!

 

?Cu(s) + ?HNO₃(aq) -> ?Cu(NO₃)₂(aq) + ?H₂O(l) + ?NO(g)

 

And this is the same thing too for this equation, somehow I get stuck with the H's. Am I doing the process wrong?

 

S₂Cl₂ + NH₃ -> N₄S₄ + NH₄Cl + S₈

 

Thank you so much in advance!

C

I'm so rusty at this but here's my attempt:

 

i just googled this cos i couldn't do it - http://au.answers.yahoo.com/question/index?qid=20080201232639AARCrDo

 

3Cu + 8HNO₃ ----> 3Cu(NO)₂ + 4H₂O + 2NO

 

this one was easier

 

There are 8+4 S on the right so you need that on the left hence 6S₂Cl_2. This means you've got to have 12 Cl too, Hence 12NH₄Cl. This means you've now got 12 + 4 Nitrogen on the right, hence 16 NH₃ on the left. 3*16 H = 12*4 H.

 

6S₂Cl₂+ 16NH₃ --> N₄S₄+ 12NH₄Cl +S₈

 

i hope someone else comes up with a better answer to the first problem. probably shouldn't have put this in the organic chemistry section though although you've been a member longer than i have