needimprovement Posted September 15, 2010 Share Posted September 15, 2010 (edited) Can anyone spot the error in this fallacy <prepared>a + b = t <prepared>(a + B )(a - B ) = t(a - B ) <prepared>a^2 - b^2 = ta - tb <prepared>a^2 - ta = b^2 - tb <prepared>a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4 <prepared>(a - t/2)^2 = (b - t/2)^2 <prepared>a - t/2 = b - t/2 <prepared>a = b Therefore all numbers are the same! Edited September 15, 2010 by needimprovement Link to comment Share on other sites More sharing options...
TonyMcC Posted September 15, 2010 Share Posted September 15, 2010 (edited) surely line 2 should be ( a+B )( a-B )= a^2 - B^2 ? Edited September 15, 2010 by TonyMcC Link to comment Share on other sites More sharing options...
D H Posted September 15, 2010 Share Posted September 15, 2010 Can anyone spot the error in this fallacy Right here. <prepared>(a - t/2)^2 = (b - t/2)^2<prepared>a - t/2 = b - t/2 Link to comment Share on other sites More sharing options...
the tree Posted September 15, 2010 Share Posted September 15, 2010 You've really got to stop posting such embarrassingly easy 'puzzles'. Link to comment Share on other sites More sharing options...
needimprovement Posted September 16, 2010 Author Share Posted September 16, 2010 You've really got to stop posting such embarrassingly easy 'puzzles'. Thank you for your comment. Link to comment Share on other sites More sharing options...
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