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Kc and Kp

gulalai
in Applied Chemistry

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i just want some one to explain to me the factors that effect kc and kp of solution

Kc and kp are effected by:

 

R = gas constant, (0.08206)

T = temperature,

nP = total moles of gaseous products

nR = total moles of gaseous

 

the mathematical relationship between the two constants, Kc and Kp, is:

Kp = Kc(RT)^(nP - nR)

Edited by liambob1

  • Author

Kc and kp are effected by:

 

R = gas constant, (0.08206)

T = temperature,

nP = total moles of gaseous products

nR = total moles of gaseous

 

the mathematical relationship between the two constants, Kc and Kp, is:

Kp = Kc(RT)^(nP - nR)

 

and if it is just an equilibrium with liquids and solids does moles still effect the constants

If any of the reactants or products are solids or liquids, their concentrations are equal to one because they are pure substances

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