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Calculation

Littlebear
in Homework Help

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Can someone please take a look at this and tell me where I am going wrong?

 

It’s part of a calculation for an Enzyme Activity Assay.

 

My enzyme solution prep is as follow: 0.02g to 50mL with deionised water (stock), 1 mL of stock to 200 mL with deionised water. 0.5mL of this is added to the reaction mixture (RM) – total volume of reaction mixture is 10.0mL.

One of the parameters in the activity calculation is - (mg of enzyme / RM)

so is it just a case of (20*1*0.5)/(50*200*10) = 1 x 10-4 – 0.0001 mg/mL of reaction mixture

 

Any help appreciated.

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