alejandrito20 Posted April 20, 2010 Share Posted April 20, 2010 hello i understand that in a flat space the metric is [math]\eta_{uv}dx^udx^v[/math]...i know that this means that the light follows straight geodesic in this space time... but ¿what would means that metric is [math]f(t)\eta_{uv}dx^udx^v[/math] where f(t)=infinite in t=0 and f(t)=0 in t=infinite.....obvious i understand the matematics, but physically ¿what means?.....for example..¿what means that in bing bang in t=0 f(t)= infinite???? Link to comment Share on other sites More sharing options...
ajb Posted April 21, 2010 Share Posted April 21, 2010 Assuming something like [math]t =x^{0} [/math] the metric you present looks conformally equivalent to the Minkowski metric. (Not sure if the [math]f(t)= 0[/math] or the [math]f(t)= \infty[/math] course trouble, so maybe mod that and the statement that the function is positive). Link to comment Share on other sites More sharing options...
alejandrito20 Posted April 22, 2010 Author Share Posted April 22, 2010 Assuming something like [math]t =x^{0} [/math] the metric you present looks conformally equivalent to the Minkowski metric. (Not sure if the [math]f(t)= 0[/math] or the [math]f(t)= \infty[/math] course trouble, so maybe mod that and the statement that the function is positive). yes [math]t =x^{0} [/math] , [math]f(t=0)=\infty[/math],[math]f(t=\infty)=0[/math], f(t) is positive. the metric in t= 0 is [math]\infty \eta_{uv}dx^u dx^v[/math], in [math]t=\infty[/math] is [math]0\eta_{uv}dx^u dx^v[/math]..... physically....¿what would mean this??? Link to comment Share on other sites More sharing options...
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