EdTheHead Posted April 12, 2010 Share Posted April 12, 2010 Solve for t: y0e-kt = y0 / 2 y0 > 0, k >0 I have no idea how to approach this problem. I don't even know what category this falls under so I'm having trouble googling info this type of problem. Link to comment Share on other sites More sharing options...
timo Posted April 12, 2010 Share Posted April 12, 2010 I don't see your problem. What if [math]y_0[/math] was called c? Do you think that would make a difference? Does "solve [math] ce^{-kt} = \frac c2[/math] for t" look easier to you? If so, then solve that. If not, then there must be something special about the [math]y_0[/math] that you did not tell us. The way the problem is stated it is just some non-zero constant. Link to comment Share on other sites More sharing options...
EdTheHead Posted April 13, 2010 Author Share Posted April 13, 2010 My main problem is I don't know why they give me the info "y0 > 0, k >0". I can isolate t and get t = ln0.5 / -k but I'm assuming they give me that extra info so I can figure out what k is in order to fully solve for t. Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted April 13, 2010 Share Posted April 13, 2010 k has to be nonzero so that your equation there won't have division by 0. If y0 were 0, the equation would be ludicrously simple, since it'd just be 0 = 0. The constraints are just there to make it all work. 1 Link to comment Share on other sites More sharing options...
EdTheHead Posted April 14, 2010 Author Share Posted April 14, 2010 Ah right. Thanks. Link to comment Share on other sites More sharing options...
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