I'm just getting stumped on how to go on this one. I'm supposed to draw the major organic product formed at each step.

 

A) I figure the bromine is added but can't decide where. I think it would go on the propyl chain but am not sure.

 

B) Second part I see as an E2 reaction forming a double bond wherever the bromine is removed from.

 

C) Third part I thought those were were used to break a triple bond and insert a double bonded O as well as some H. But of course I've formed no triple bonds anywhere.

 

So as you can see, I'm just all lost

 

 

in first step free radical will be generated hence substitution on aromatic ring is unlikely. Br radical would prefer secondry position on propyl chain ie at position 3 (numbering the c attached to ring as 1) as then radical formed will have resonance stablizing effect of phenyl ring. i also think second step is formation of double bond. third one is hydro boration reaction with introduction of alcohol