blackhole123 Posted September 2, 2009 Share Posted September 2, 2009 (edited) The average concentrations of bromine in seawater (d=1.024g/mL) and the Dead Sea (d=1.22g/mL) are .065g/L and .50g/L, respectively. What is the mass ratio of bromine in the dead sea to that in seawater? I have no clue what to do here. The answer is 7.7/1 but I can't get there. Is this testing significant figures? EDIT: Wow was I overthinking this. Just divide the two concentrations to get 7.69 which is 7.7..... don't I feel foolish. Edited September 2, 2009 by blackhole123 Link to comment Share on other sites More sharing options...
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