aaronaldo Posted January 28, 2009 Share Posted January 28, 2009 I need to work out a perctange yield for my experiment, however i am having trouble balancing the equation. H2SO4 + C6H5Br + HNO3 --------------> C6H4BrNO2 + H2O this is what i have so far.. but there is no S on the right side of the equation.... im very confused. Link to comment Share on other sites More sharing options...
Tartaglia Posted January 28, 2009 Share Posted January 28, 2009 H2SO4 is basically a catalyst, it is returned at the end Link to comment Share on other sites More sharing options...
vedmecum Posted January 29, 2009 Share Posted January 29, 2009 hye . you can't calculate the exact percentage of the product by simple chemical equation because their are other factors which affect the reaction rate for ex relative proportion of h2so4 and hno3 , effect of bromine , and the most factor orientation i.e. o and para product . i know these makes your problem more complicated but ........ Link to comment Share on other sites More sharing options...
hermanntrude Posted January 29, 2009 Share Posted January 29, 2009 vedmecum, i think that aaronaldo is saying he wants to find the percentage yield based on an actual yield he has either got or been given. Link to comment Share on other sites More sharing options...
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