bob000555 Posted November 28, 2008 Share Posted November 28, 2008 Which would be the more likely result of passing gaseous iodine over sodium amide: NaNH2 + 2I2 -> 2HI + NaNI2 or NaNH2 + I2 -> NaI + NIH2 The first reaction would produce a much more interesting product, NaNI2, the second seems like a way a good way to inhale a poisonous explosive… Link to comment Share on other sites More sharing options...
Tartaglia Posted November 29, 2008 Share Posted November 29, 2008 I would expect hydrazine as the first product 2NH2- + I2 --> N2H4 + 2I- Link to comment Share on other sites More sharing options...
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