Jump to content

gravity correction- latitude correction

Featured Replies

i have i problem with many parts to it that the forums may be able to help me with. ive been given a scenario which involves gravity surveys along a path, in summary here it is:

 

a gravity survey is taken at an initial latitude of 45 degrees and has an azimuth of 30 degrees.

 

ive also been given a list of gravity data readings, but its not the problem. the question asks to apply necessairy corrections and i know latitude correction is one. my problem is how to determine the correction for each reading given. i know i have to draw a triangle from the start (45 degrees) and a line going out from there 30 degrees. i have found the distance ive traveled north when i travel along the azimuth.

 

we have been given a correction formula: g= -8.108 sin 2 theta where theta is the given degree of latitude.

 

at this point i am stuck. how do you find the correction for example if i move 25.98 meters in a north direction?

Archived

This topic is now archived and is closed to further replies.

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.