512349652

124876251

210012201

123648520

601586310

474808785

511665579

243155817

386529906

615204101

515987632

552103492

518979642

122011148

741085290

968647954

987654321

625316623

 

Arrange these eighteen 9-digit numbers so that half of them are horizontal and half are vertical, so that every number is used once, no more no less. The numbers will criss-cross, so that digit A1 is both the first vertical number's first digit and the first horizontal number's first digit, and I9 is the same way, only replace "first" with "last."

 

This is all the help you will get from me. Help each other, do not expect to do it by yourself. This is like Sasuke, a.k.a. Ninja Warrior; a win for one is a win for everybody. Good luck.

 

Edit: Correction: I will help you in one scenario: If you have a question about the instructions, I will answer them. Other than that, you must rely on each other for assistance.

what do you refer to as *first* , *last* *vertical* and *horizontal* numbers? in a matrix where you have not described any order and expect an order to be found! I am assuming there isnt any

First verticle number is the number that goes vertically in the A column. Same with first horizontal, only it's row 1. Last columns and rows are I and 9, respectively. It looks like this:

 

A1 B C D E F G H I

2- - - - - - - - - -

3- - - - - - - - - -

4- - - - - - - - - -

5- - - - - - - - - -

6- - - - - - - - - -

7- - - - - - - - - -

8- - - - - - - - - -

9- - - - - - - - - -

 

Replace the dashes with a digit so that nine of the 18 numbers are horizontal and nine of them are vertical in a 9x9 matrix.

It's kind of like SATOR AREPO TENET OPERA ROTAS...

 

SATOR

AREPO

TENET

OPERA

ROTAS

 

Only with numbers...

^^^Exactly, for example, if I were using a 2x2 matrix, the numbers 14, 23, 12, and 43 would be arranded like this.

 

14

23

 

14 is row 1. 23 is row 2. 12 is column A, and 43 is column B. Get it?