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Spectroscopy


srose9625

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Okay for 6B #1 you have a proton signal at >10 which strongly suggests a caboxylic acid, the remaining 3 signals correspond to a 3 carbon fragment where all the protons are in different environments i.e. two triplets and a hextat (n+1 rule)

 

6B #2 you have a proton in the 9-10 range, strongly suggesting an aldehyde and the two reamining signals and 3 carbons, this means symmetry in the molecule so two signals are equivalent

 

6A #4 is very similar to 6B #1 except its a bromoalkane instead of the acid

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