Jump to content

Linear Algebra

Featured Replies

I did the work but not sure if its right, also my professor likes us to include every detail(including all the Vector space Axion) , if there is another way of proving it, more elegant,, please help,, thanks

 

1) Let V be the set of all pairs (x,y) of real numbers with the addition + and scalar multiplication* defined by:

(x1,y1)+(x2,y2)= (x1 + x2 , y1+y2) and c*(x,y)=(x,cy)

 

Show that V with the above operation is not a vector space. Find at least one axiom that fails and give an example showing that the axiom fails..

 

***Let α = (x, y)

Then for real numbers a and b we have

(a + b) α = (a + b) (x, y)

= ( x, (a+b)y )

 

Now aα = a(x, y)

= (x, ay)

bα = b(x, y)

= (x, by)

and aα + bα = (x, ay) + (x, by)

= ( 2x , ay + by)

(a + b) α

Therefore, V is not a vector space.

yeah that violates distributivity, which I believe is an axiom of vector spaces

Archived

This topic is now archived and is closed to further replies.

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.