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Chemical reaction with Benzene


dcowboys107

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Benzene (C6H6) reacts with nitric acid. Two products are produced, one of which is water. The other product is an oily liquid which has molar mass of 213 g/mol. It contains 33.8% Carbon, 1.42% Hydrogen, 19.7% Nitrogen, and 45.08% Oxygen. Write a balanced equation complete with descriptive symbols for this reaction.

 

I converted each to moles so for carbon I got 2.816, Hydrogen 1.42, and Nitrogen, 1.407 and oxygen 2.8175. Then I divided by the smalles and expressed to a whole number ratio. So for each one respectively: Carbon 2, Hydrogen 1, Nitrogen 1 and Oxygen 2. So the supposed emperical forumula should be C2HNO2. The molar mass for the molecular formula is 213 g/mol I divided the molar mass of the empirical formula and divided into 213 and got 3.

My final answer turned out to be C6H3(NO2)3. I feel suspicous that this is incorrect. My equation is this: C6H6(l) + HNO3(Aq) ----> H2O(l) + C6H3(NO2)3.

 

What did I do wrong? please show me and if you wouldn't mind checking to see if my symbols are right, etc. Thanks!

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it`s actualy a solid at room temp, like crystals with a yellow color.

it`s only slightly soluble in water, a bit like 2,4,6 Trinitrophenol, so you`de be lucky to get a gram dissolve in a liter of water.

 

as for a descriptive symbol, what do you mean?

it`s a simple Benzene ring with a Nitronium ion (O2N) at positions 1,3 and 5. there`s no other simple way to describe it :)

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