# 98% of H2SO4 solution

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I have problem to determine the molarity of H2SO4 from 95%-98% H2SO4 solution with volume of 2.5 L stated on the bottle.

Besides, i am not sure what is the meaning of 95%-98%. Is this percentage is in term of volume, number of moles or weight of H2SO4?

If the molarity above is obtained, suppose i mix 1 volume this H2SO4 with 2 volume of water, what is the new molarity and number of moles of the diluted solution?

*Are these informations useful?*

density of H2SO4 = 1.841 g/cm3

Molecular mass of H2SO4 = 98.08 g/mol

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98%

means that the H2SO4 has 98% of the total weight of a sample of H2SO4 solution.

In order to find out the molarity of the sulphuric acid,

there's a pretty good method.

Find out how many moles of H2SO4 are there in 1 dm^3 of water.

Then it is equal to the molarity of the acid.

what is the new molarity and number of moles of the diluted solution?

Molarity= no. of mole of a substance / volume of solution.

Since there's no departure of any H2SO4 molecules,

it follows that there exists the amount of H2SO4 molecules.

In this case , the molarity decreases as a result of the decrease in Volume of the solution

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Thank you. This website is useful!

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I have calculated the molarity of the solution = 18 M

After dilution, the new molarity is roughly 6M. However, is this possible to use this diluted solution outside fume cupboard? What i understand is 6M is too concentrated to be used outside fume cupboard.

But, during my experiment, this diluted solution was placed on the bench only. Hmm......i think i have make mistake in calculation!

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But, during my experiment, this diluted solution was placed on the bench only. Hmm......i think i have make mistake in calculation

What does this mean?

You didn't use the diluted solution?

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After dilution' date=' the new molarity is roughly 6M. However, is this possible to use this diluted solution outside fume cupboard? What i understand is 6M is too concentrated to be used outside fume cupboard.

[/quote']

I suppose technically, you could use even an 18M solution of H2SO4 outside a fume hood, depending on the type of experiment you are using it for. Of course, it's not recommended, but not everyone has access to a fume hood.

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What does this mean?

You didn't use the diluted solution?

The H2SO4 put on the bench is diluted solution already. Diluted solution is made by mixing 1 volume of H2SO4 and 2 volume of H2O. (Eg. 5mL of H2SO4 + 10mL of H2O). The molarity of the diluted H2SO4 should be 6M if the formula MV = MV is applied. Am i correct?

If yes, is 6M of H2SO4 safe to use outside fume cupboard? (From mt knowledge, 6M is very concentrated too!)

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