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Reduction potential

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Consider the following reduction potentials:

Cu2+ + 2e- --> Cu E° = +0.34 V

Pb2+ + 2e- --> Pb E° = -0.13

For a galvanic cell employing the Cu, Cu2+, Pb, Pb2+ couples, calculate the maximum amount of work (in kJ) that would accompany the reaction of one mole of lead under standard conditions.

Hmmmmm help plz :cool:

V = High - low = 0.34-(-.13) = 0.47 V

 

Faradays used = 2 as Pb is oxidised to dication

 

E = V*Q = 0.47 * 2 *96500 J

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