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logarithms and differentiation

rhiannon
in Mathematics

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please can someone solve 2e^5t to 3 significant figures.

Sorry but people will not do your work for you, people will however help you if you get stuck.

 

Here is a hint:

 

[math]\frac{d}{dx} \, ne^{x} \, = \, ne^{x}[/math]

 

Cheers.

 

Ryan Jones

The answer is also 'no' because 2e^5t is not something that can be 'solved' in the first place, never mind to some number of significant digits.

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