I got this question from my Chem lab:

 

Al(NO3)3 + Na2CO3 -> white precipitates

 

White precipitate + HNO3 -> bubbles & precipitates dissolved

 

 

Can someone kindly tell me what does the Ionic Equation for the above actions would look like??? Because I'm having difficulties in writing its Ionic Equations >.<

 

 

Thank you so much!

Actually there is no Redox reaction takes place !!!

 

So :

 

1) 2 Al 3+ + 3 CO3 2- -----> Al2(CO3)3 ( white ppt )

 

 

2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O

2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O

A tiny difference from my answer.

In my region, we would put down the precipitate instead of just the ion.

Oh Thank you so much~!!

 

That's great help!

1) 2 Al 3+ + 3 CO3 2- -----> Al2(CO3)3 ( white ppt )

2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O

 

The precipitate loses CO2, and the Al(OH)3 begins to lose water, forming polymers of aluminum oxide in a meshwork molecular structure, until in the limit, only Al2O3 would be left. It won't go all the way to alumina unless the water is removed by filtering and heating.

 

Dangerous Bill