Help me , please. how to prepare these compose from benzene:

 

1,4-dibromobenzene

1,4-dinitrobenzene

C6H5-CH2NH2

acid m-bromobenzoic

5-phenyl-2-metylphenol

 

merci beaucoup!

anyone can provide a helping hand !!!!

 

Im interested to know the answer also !!!??

1,4 dibromobenzene can be made by direct Friedel Krafts halogenation, but it would have to be separated from the ortho product.

para dinitrobenzene would have to be made in a roundabout fashion eg using the sandmeyer reaction as nitro is a meta director

 

C6H6 ---> C6H5NO2 ---> C6H5NH2 ---> p + o C6H4(NO2)(NH2)

 

p-C6H4(NO2)(NH2) ---> p-C6H4(NO2)(N2)+ ---> p-C6H4(NO2)2

 

For C6H5CH2NH2, direct chloro methylation can be carried out using HCHO +HCl with a ZnCl2 catalyst will give benzylchloride which will easily undergo SN1 displacement by NH3

 

m-C6H4BrCO2H can got from the Gatterman Koch formylation of benzene to produce benzaldehyde, followed by oxidation followed by Friedel Krafts bromination

 

The last one I'll have to think about