kidia Posted March 21, 2006 Share Posted March 21, 2006 How can I Compare the magnitudes near the earth’s surface of the weight of an electron and a typical magnetic force exerted by the earth’s magnetic field (B = 10-5T) on an electron with speed 10 m/s. As I understood Weight of electron = mg Magnetic force=qBv am I right? Link to comment Share on other sites More sharing options...
timo Posted March 21, 2006 Share Posted March 21, 2006 Mostly. Strictly speaking the magnitude of the magnetic force is qBv*|sin(a)| where a is the angle between the direction of the magnetic field lines and the movement direction of the electron. But if you´re only interested in the case where the electron moves perpendicular to the field, then your equations are ok. Link to comment Share on other sites More sharing options...
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