[Chem-Applied] Vapour pressure of Pure Liquids A & B are 450 & 700mmHg respect. @350 K . Find comp. of liquid mix, total Vapour pressure is 600mmHg and Vapour phase composition

xA and xB are mole fractions of each components - Vapour-liquid phase ? why is AI saying it's liquid phase composition ?

Henry's Law : p = KH x “partial pressure of as in vapour phase (p) is proportional to ole fraction of gas (x) in solution” and is expressed as:

Raoult’s Law: A=xA pA∘

pi = yi P total - this is the ratio of 2 components in vapour phase

AI Solved -

Given:
p°A = 450 mm Hg
p°B = 700 mm Hg
Total vapour pressure, P = 600 mm Hg

Let xA be the mole fraction of A in the liquid phase.
Then xB = 1 − xA

Using Raoult’s law:
P = xA·p°A + xB·p°B

600 = 450xA + 700(1 − xA)
600 = 700 − 250xA
xA = 0.40

Therefore:
xA = 0.40
xB = 0.60

Partial vapour pressures:
pA = xA·p°A = 0.40 × 450 = 180 mm Hg
pB = xB·p°B = 0.60 × 700 = 420 mm Hg

Vapour phase composition:
yA = pA / P = 180 / 600 = 0.30
yB = pB / P = 420 / 600 = 0.70

Final Answer:

Liquid phase composition:
xA = 0.40
xB = 0.60

Vapour phase composition:
yA = 0.30
yB = 0.70