Dhamnekar Win,odd Posted April 27, 2022 Share Posted April 27, 2022 Answer to question (b) assumes Maxwell-Boltzmann statistics. But how to show that the probability of each distinguishable distribution is [math]n*(N)^r ?[/math] Why is Bose-Einstein statistics impossible here? Each distinguishable distribution have equal probability of [math]\frac{r!(n-1)!}{(n+r-1)!}[/math] under Bose-Einstein statistics. Link to comment Share on other sites More sharing options...
Dhamnekar Win,odd Posted April 28, 2022 Author Share Posted April 28, 2022 (edited) Please read 'Answer to question (b) assumes Maxwell-Boltzmann statistics. But how to show that the probability of each distinguishable distribution is [math] \frac {1} {n*N^r} [/math] ?' What is meaning of Note given? Edited April 28, 2022 by Dhamnekar Win,odd Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now