Sarahisme Posted August 14, 2005 Share Posted August 14, 2005 ok here is question and my answers...: [math] \lambda=2L=2\times0.580m=1.16m [/math] [math] \mu=\frac{M}{L_(wire)}=\frac{0.00225kg}{1.00m}=0.00225(kg/m) [/math] [math] v=\sqrt{\frac{F}{\mu}}=\sqrt{\frac{29.4N}{0.00225}}=114.3(m/s) [/math] [math] f=\frac{v}{\lambda}=\frac{114.3(m/s)}{1.16m}=98.54 \ Hz=98.5 \ Hz [/math] how'd i do? -Sarah Link to comment Share on other sites More sharing options...
Sarahisme Posted August 14, 2005 Author Share Posted August 14, 2005 ... Link to comment Share on other sites More sharing options...
DQW Posted August 14, 2005 Share Posted August 14, 2005 how'd i do? Link to comment Share on other sites More sharing options...
Sarahisme Posted August 15, 2005 Author Share Posted August 15, 2005 i take that as an, everything is perfectly correct?? Link to comment Share on other sites More sharing options...
DQW Posted August 16, 2005 Share Posted August 16, 2005 i take that as an, everything is perfectly correct?? Link to comment Share on other sites More sharing options...
Sarahisme Posted August 16, 2005 Author Share Posted August 16, 2005 lol, cheers DQW! Link to comment Share on other sites More sharing options...
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