Sarahisme Posted August 10, 2005 Share Posted August 10, 2005 hi all, here is the question, i will post my answer in the next post: Sarah Link to comment Share on other sites More sharing options...
Sarahisme Posted August 10, 2005 Author Share Posted August 10, 2005 for part (a) use the equation for adding relativistic velocites together [math] u=\frac{u^{'}+v^{'}}{1+\frac{u^{'}v^{'}}{c^{2}}} [/math] So u = the speed of one ship relative to the other. [math] u=\frac{0.6c+0.6c}{1+\frac{(0.6c)^{2}}{c^{2}}} =\frac{1.2c}{1.36} =0.88c = 0.9c [/math] oh by the way, how do you make an equation go to the next line using latex? eg. u=42x = ... =.... etc. Link to comment Share on other sites More sharing options...
Sarahisme Posted August 10, 2005 Author Share Posted August 10, 2005 for part (b) again use the equation for adding relativistic velocites together [math] u=\frac{u^{'}+v^{'}}{1+\frac{u^{'}v^{'}}{c^{2}}} [/math] So u = the speed of one ship relative to the other. [math] u=\frac{30000+30000}{1+\frac{(30000)^{2}}{c^{2}}} =\frac{60000}{1\times10^{-8}} =59999.9994(m/s) =6.0000\times10^{4} [/math] and the final answer should be too 5 sig. figures, as the information given in the question (for part b) is to 5 sig. figs. so what did people think of all that? i am pretty damn sure its right! Link to comment Share on other sites More sharing options...
timo Posted August 10, 2005 Share Posted August 10, 2005 [math] \begin{array}{rcl} a &=& b + c \\ &=& (b + d) - (d-c) \end{array} [/math] Source: \begin{array}{rcl} a &=& b + c \\ &=& (b + d) - (d-c) \end{array} Your answers look good. Especially part b) which gives the classical result as one would expect at such low velocities. Link to comment Share on other sites More sharing options...
Sarahisme Posted August 11, 2005 Author Share Posted August 11, 2005 [math] \begin{array}{rcl} a &=& b + c \\ &=& (b + d) - (d-c) \end{array} [/math] Source: \begin{array}{rcl} a &=& b + c \\ &=& (b + d) - (d-c) \end{array} . what this about? Link to comment Share on other sites More sharing options...
DQW Posted August 11, 2005 Share Posted August 11, 2005 It's about this : oh by the way' date=' how do you make an equation go to the next line using latex?[/quote'] Link to comment Share on other sites More sharing options...
Sarahisme Posted August 15, 2005 Author Share Posted August 15, 2005 oh right, oops , thanks Link to comment Share on other sites More sharing options...
Sarahisme Posted August 15, 2005 Author Share Posted August 15, 2005 oh so you have to have all this array stuff...? Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now