hey

 

i am not sure whether i am getting this problem correct...

 

i reckon the answer would be:

 

f(n) = nv/{lamda1} ; where n = 1, 3, 5, 7, . . .

 

{lamda1} being the fundamental harmonic's wavelength,

and

v being the speed of sound in air

 

well anyway, thats what i think the answer is but yeah i am new to thise stuff, so just thought i'd check

 

-Sarah

Except recall that with one end closed, the reflected standing wave is 2x the pipe length...

It looks to me like you're choosing odd harmonics, but all harmonics should be considered. Perhaps you are trying to double the frequency by this method. But in this case the fundamental harmonic will be the wrong one.

It has been a long time since I read Helmholtz on sound waves and organs. I will go have a look for something and come back to you...

hey

 

i am not sure whether i am getting this problem correct...

 

i reckon the answer would be:

 

f(n) = nv/{lamda1} ; where n = 1' date=' 3, 5, 7, . . .

 

{lamda1} being the fundamental harmonic's wavelength,

and

v being the speed of sound in air

 

well anyway, thats what i think the answer is but yeah i am new to thise stuff, so just thought i'd check

 

-Sarah[/quote']

Your answer is perfectly correct.

 

I hope you understand exactly why this is true - that's the important part.

 

All you have to do is draw a couple of pictures, and the rest follows automatically.

ok thanks DQW