SwollBoyMax Posted May 3, 2018 Share Posted May 3, 2018 Write the balanced equation for the decomposition of hydrogen peroxide into water and oxygen gas. a. 2H2O2 → 2H2O + O2 Use Hess’ Law to calculate the net energy released. Then calculate the energy in kJ/ mol—this will be the theoretical value: H2 + ½ O2 → H2O ΔH = -286 kJ/ mol H2 + O2 → H2O2 ΔH = -191 kJ/ mol H2O2 + H2 + ½ O2 → H2 + O2 + H2O H= -95 kJ/mol H2O2 → ½ O2 + H2O H= -95 kJ/mol I am not sure what the answer to the second part is. I think that it is either -95 kJ/mol or -190 kJ/mol. I just want to make sure which one it is. Link to comment Share on other sites More sharing options...
Acreator Posted May 11, 2018 Share Posted May 11, 2018 It is -190 kj/mol Because 2H2 + O2 -> 2H2O H= -572 kj/mol 2H2O2 -> 2H2 + 2O2 H= 382 kj/mol 2H2 + 2O2 + 2H2O -> 2H2O2 +2H2 + O2 H= 190 kj/mol 2H2O2 -> O2 + 2H2O H= -190 kj/mol -572+382+190-190= -190kj/mol Link to comment Share on other sites More sharing options...
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