Martinez Posted May 31, 2005 Share Posted May 31, 2005 Let's consider the inscribed square of the circle such that its vertices describe the chords to its 4 quadrants and where area of the circle is, say, 64 units. Area of the inscribed square is given as 64/0.5 pi = 40.5 square units and where each line of the square defines the chord length to a quadrant of the circle. That chord length is given by the trianglature formulae of r*sqrt 2 = chord length; chord length*pi/4*sqrt 2 = quadrant arc length. The trianglature formulae derives from aeronautics engineer and writer E.P. LeRoy. Link to comment Share on other sites More sharing options...
Martinez Posted June 2, 2005 Author Share Posted June 2, 2005 I keep working on it and have now come up with a formulae giving further evidence that it is not pi that officiates in determining dimension of the circle but root 2. Here is the formulae I come up with: Sqrt of area/sqrt pi = radius; r^2*pi = area. Thus for the given area of 64: 8/sqrt pi = 4.5135....radius; r^2*pi = 64 area. Root 2 Rules! Link to comment Share on other sites More sharing options...
Martinez Posted June 4, 2005 Author Share Posted June 4, 2005 I keep working on it and have now come up with a formulae giving further evidence that it is not pi that officiates in determining dimension of the circle but root 2. Here is the formulae I come up with: Sqrt of area/sqrt pi = radius; r^2*pi = area. Thus for the given area of 64: 8/sqrt pi = 4.5135....radius; r^2*pi = 64 area. Root 2 Rules! Aye Caramba!... Hold on to your hat everyone! It would appear that not only dioes root 2 rule - but that it is as well sacosanct! - for it is now seen that applying the formulae to any area and applying any known pi value whatsoever results in deriving the same area. Root 2 would appear indeed to be sacrosanct! - pi but the ratio of line to arc. What say y'all? Link to comment Share on other sites More sharing options...
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