hey, just double checking this stuff (i have only just begun this topic in maths and so i am a little shaky on it)

 

is the answer to this:

 

i) no , because the zero vector is not in the set H.

 

ii) yes, but i don't know how to explain why, i guess if you let s and t be zero, then the zero vector is part of the set L , and obviously if you add any two vectors it will still be in L and if you multiple by a scalar it will be too...

 

anyways, yeah as i said, i'm a greenhorn with this stuff, so take pity

 

Sarah

ii) yes, but i don't know how to explain why, i guess if you let s and t be zero, then the zero vector is part of the set L

 

Yes.

 

 

 

and obviously if you add any two vectors it will still be in L and if you multiple by a scalar it will be too...

 

so you've got a vector space, and all is well - it;s the span of the vectors (1,2,1) and (3,3,6)

sorry, i've never heard of vector space..??

 

and i gather i got part i) right then ?

Both parts are right, and if it helps don't see the word "vector" before the word space, just see sub, since they are in this case the same thing

oh ok then, thanks matt