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King Thando Mathe

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Posts posted by King Thando Mathe

  1. The Doppler Effect is accounting for relative movements of source and observer at constant velocity meaning changes in frequency are sudden but remain constant.

    Now can we also have source and observer moving at accellarations and frequencies changing at certain rates?

  2. A small bead of mass m is threaded on to a smoth circular wire of radius r and centre O fixed in the vertical plane.Bead is projected with speed u from its highest point, A, of the wire.Find the reaction on the bead due to the wire when at P,in terms of m,g,r,u and ₩;where ₩ is the acute angle AOP.

  3. It will never reach the end

     

    let length be L, velocity be U , acceleration be A and time be T

     

    Li=1m, Lf=?

    Ui=1m/s, Uf=?

    A=?

     

    Uf=Ui+AT

    Uf=Ui, T=0

     

    A=Uf/1= 1m/Square sec

     

    Lf=1/1=1m

     

    Lt= Li+Lf

    Lt=2m

     

    t=2/0.00001

    t=200000s

     

    conclusion: the bug will reach the end in 200000 seconds by crawling a distance of 2 meters.

     

    Uf=Ui=1m/s for the band's end because we assume constant rates

  4. The momentum and KE are shared between the two bodies in any collision.But in the 'idealised' situation of perfectly elastic collisions,the approaching mass will donate all its KE to the other body or will impart some.The basic rule z ENERGY WILL NOG BE LOST AS OTHER FORMS.A body can thus continue to move (or after rebound) with a reduced velocity because it has shared its KE.

     

    The momentum and KE are shared between the two bodies in any collision.But in the 'idealised' situation of perfectly elastic collisions,the approaching mass will donate all its KE to the other body or will impart some.The basic rule z ENERGY WILL NOG BE LOST AS OTHER FORMS.A body can thus continue to move (or after rebound) with a reduced velocity because it has shared its KE.

  5. 1)Working from tbe momentum eqtn will certainly have you assume that velocity of A is 0 after collision.Thus Pa will become equal to Pb and a ratio of 1 which therefore is less than 2.

    2)Working from the conservation of Kinetic Energy,will Pa/Pb=Vb/Va.Vb cannot be twice Va[ That we all know] since Vb is influenced by Va.

    3)One can also create: Pa = [-(Pa-Pb)] + Pb

    This will lead to Pa=Pb again.If one does not want to apply that A is stationary after collision then Pa after collision can be regarded as [-(Pa-Pb)].But thesevis somehow bizzarre.

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