Raffael

 

 

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BARROW =71

NEWTON =70

WHISTON =104

SAUNDERSON=129

COLSON = 51

WARING =92

MILNER =58

WOODHOUSE=108

TURTON =80

AIRY =46

BABBAGE =84

KING =45

LARMOR =58

DIRAC =52

LIGHTHILL =130

HAWKING =____?

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Text is the same as before and your objective is to figure out

professor's Hawking numerical value .

 

The situation here is a little bit different becouse now you have 19

unknowns but "only" 15 simultaneous equations at first glance.

Brute force approach will not work again.

However,just like in the previous puzzle the solution is unique.

 

A=17,B=5,C=9,D=1,E=13,G=22,H=26,I=11,K=2,L=6,M=4,N=10,O=3,R=14,S=20,T=16,U=21,W=18,Y=4

Is there room for another solution under assumption that values were taken from set {1,2,3,...,26}?

 

 

:-) :-) :-) :-) :-) :-) :-) :-) :-) :-) :confused:

"-""M""T" "V""H" "A""E" "O""I" "U""B" "G" "K""P" "S""F""W""Z"GAP "C""L" "N""R" "D""-" "-"

 

All other available values are outside of the span of values, so in that case Y could have any value.

 

Since it should be solvable and there is only one gap, I guess thats where Y belong.

In the "Feynman" puzzle I'd rather go with Y=26.

You have a neat regularity(pattern) in ascribing the values to the letters you're supposed to find.

A little help-notice how grouped the vowel's values are : A=6,E=7,I=9,O=8,U=10.

Coincidence?I don't think so...