Alexander Masterov
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Posts posted by Alexander Masterov
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Results of experiments with the beta-spectrometer, which (allegedly) demonstrates the relativistic increase in mass, are interpreted incorrectly:
Deviation of the trajectories of relativistic electrons from the trajectories (defined by the classical theory of electromagnetism and Newtonian mechanics) is due to weakening of the magnetic field effect on the relativistic particle, but does not increase the mass of a relativistic particle. In other words, should adjust classic expression of Lorentz force, since mass are an absoluteness (speed-independent).
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Neutrino has an unlimited ability to penetrate into matter.
Relativistic neutrons seek to do so if their rate tends to the speed of light.
Cherenkov's effect does not interfere for a neutrons.
The charged particles would behave the same way as the neutron, if Cherenkov effect were not interfere.
However, all particles (electrons and positrons - too) get unlimited ability to penetrate into matter, if their speed more than the speed of light.
Cherenkov's effect does not operate at speeds exceeding the speed of light in a vacuum.
Any (hyper-light-speed) matter has unlimited ability to penetrate into any statical matter.
All converted into neutrinos, if moving faster than light.
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Electron neutrino is a positron, whose rate is higher than the speed of light. And an electron antineutrino is an electron whose velocity is greater than the speed of light.
We can calculate the velocity of neutrinos, since the mass of the electron and positron are known.
My arguments:
1. Electron is born in a pair with a positron.
2. Mass on the velocity-independent.
3. Neutrinos move faster than the speed of light (otherwise it would not neutrinos).
Matter, whose speed is greater than the speed of light does not interact with EMF, if the source field is static. More than that, the matter (whose speed is greater than the speed of light) does not interact with a static matter. Positron seems neutral, since his speed than the speed of light. Positron does not interact with static EMF and a static matter, since has speed greater than the speed of light.
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I think that a neutrino detector can be constructed from a balloon with compressed hydrogen. (The mass of the hydrogen atom is 28 times lighter than the nitrogen molecule and 32 times lighter than oxygen, which means that hydrogen is more than five faster than any of them.)
This balloon should be lowered to great depths in the ocean. (Near Mariana Trench.) At 11 km depth, under pressure of 1,100 atmospheres, the density of hydrogen would be 1,000 times more. (100kg/m3)
In this case, hydrogen can be obtained (by electrolysis of distillate) directly into the cylinder, while immersing the container into the depths. (This - as an option.)
Can be in a different way: using a cascade of pumps at different depths.
And it is possible: instead of pumps can be used with a balloon+plunger. Hanging on the ropes these balloons (in the form of two garlands), dropping and picking up by turns - you compel them inject hydrogen into the depths.
And you can still way: Balon Dewar (with liquid hydrogen) set cylinder. The hydrogen to do evaporation - balon go down. (This option seems most appropriate.)
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Let me explain:
Neutrinos with matter should not have to interact with, and (if their rate significantly greater than the speed of light) - so be it.
Methods which try to detect neutrinos today, you can catch those neutrinos, whose rate is only slightly greater than the speed of light (more on the rate of Brownian motion).
Of the neutrino flux filtered out by those whose speed exceeds the speed of light is greater than the rate of Brownian motion of granite. Therefore, the number of neutrinos passing through the Earth increases sharply if their speed exceeds the speed of light is greater than the rate of Brownian motion in the interior of the earth.
Water molecules are lighter molecules granite. Therefore, the velocity of the Brownian motion of water molecules in two - two and a half times (the square root of mass ratio) of greater. Therefore, water molecules move twice (at least) faster than the molecules of granite. This means that there is a chance to catch the water in those neutrinos which are not extinguished in the interior of the earth, but the speed is (still) not much greater than the speed of light.
If used as a medium for hydrogen, the sensitivity will increase many times, since the rate of Brownian motion of the atoms of hydrogen is ten times higher than that of granite. Hence: the hydrogen is able to catch those neutrinos, which are almost not able to catch the granite (and water). Should be a lot of neutrinos (for which the thickness of the Earth is transparent).
And in Baykal lake to catch a cosmic neutrinos is even more difficult, because Brownian speed of motion of atmosphere much more than in water. Atmosphere do swallow up those neutrinos which could be fixed in the lake.
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I added to up.Alex, I'd like you to define exactly what you think x_1', x_2', t_1', and t_2' mean.0 -
The observer at rest:
[math] x_1 [/math] - it's path of light from right to left = distance between the mirrors.
[math] x_2 [/math] - it's path of return.
[math] -x_2 [/math] - the distance between the mirrors. ([math] x_2=-x_1 [/math])
[math] path_1 = -path_2 = x_1 [/math]
[math] t_1=path_1/c = x_1/c [/math]
[math] t_2=-path_2/(-c) = x_1/c [/math]
[math] t_1=t_2 [/math]
The observer move ([math] v>0 [/math]) for Master Theory:
[math] x_1' [/math] - distance between the mirrors for moving observer. ([math] x_1'=x_1(1-v^2/c^2) [/math])
[math] path_1' = x_1'/(1-v/c) [/math] - it's path of light from right to left for moving observer.
[math] path_2' = -x_1'/(1+v/c) [/math] - it's path of return.
[math] t_1'=path_1'/c = x_1'/(c-v) [/math]
[math] t_2'=-path_1'/(-c) = x_1'/(c+v) [/math]
[math] t_1\neq t_2 [/math]
Tese pathes is roots of this equation: [math](path'-vt)^2-(ct)^2=0[/math] and [math] path_1' \neq -path_2' [/math]
SRT pathes is roots of this equation: [math](path')^2-(ct')^2=0[/math] and [math] path_1' = -path_2' [/math]. (It's not correct.)
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[math]x_1 = -x_2[/math] and [math]x_1' = -x_2'[/math] always.Because we start with [math]x_1 = x_2[/math]. We do not get that [math]x_1' = x_2'[/math].Do you intend to contest this?
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At the moment, we're not talking about your idea. We're talking about relativity. You still have yet to show that there is a problem with it; I have shown you why your objection to it is wrong.
Additionally, in context, your post makes no sense. There is no H; there is no W.
=Uncool-
How do you get [math]t_1'\neq t_2'[/math] from [math] x^2-(ct)^2=(x')^2-(ct')^2 [/math]?
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But relativity is more than just slowing time - again, space in one frame becomes time in another. Therefore, the fact that the spatial coordinates are different can change that.
In this example:
From the frame where the walls are standing still, the events we see are:
Light rays emitted: [math](0,0,0,0)[/math]
Light ray absorbed on the left: [math](\frac{L}{c}, -L, 0, 0)[/math]
Light ray absorbed on the right: [math](\frac{L}{c}, L, 0, 0)[/math]
...
Master Theoey:
[math](\frac{L(1-v^2/c^2)}{c+v}, -L(1-v^2/c^2), H\sqrt{1-v^2/c^2}, W\sqrt{1-v^2/c^2})[/math]
and
[math](\frac{L(1-v^2/c^2)}{c-v}, L(1-v^2/c^2), H\sqrt{1-v^2/c^2}, W\sqrt{1-v^2/c^2})[/math]
OR:
[math](\frac{L(c+v)}{c^2}, -L(1-v^2/c^2), H\sqrt{1-v^2/c^2}, W\sqrt{1-v^2/c^2})[/math]
[math](\frac{L(c-v)}{c^2}, L(1-v^2/c^2), H\sqrt{1-v^2/c^2}, W\sqrt{1-v^2/c^2})[/math]
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Lorentz transformations are the result of the expression:Which is exactly what you got, up to the factor of , which is there due to the spatial dilation (the barriers are closer together than in the non-moving frame).You have to include the effects of spatial displacements.
[math]x^2-(ct)^2=(x')^2-(ct')^2[/math]
Coordinate transformations must to derive from this expression:
[math]x^2-(ct)^2=(x'-vt')^2-(ct')^2[/math]
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Slowing down time can not change the fact: [math]T_1\neq T_2[/math]This is gibberish. I think I can guess what you're saying, but I would like to make sure, so please try to reexplain.0 -
Time dilation can not align intervals of time.No, it doesn't. It alleges that the times are identical in another frame. You forget that time is frame-dependent in relativity.0 -
Ambiguity requires justification.Why not?Ambiguity requires additional physical law, which will determine the choice of ambiguity. No such law.
Dog's rate is constant always also.Which it shouldn't be, because light is traveling at the same speed in both directions, and is covering the same distance.
Dog's rate is constant always also.Because you specified the same distance to be traveled. The time should not be different - because the speed of light should be the same in all directions in all frames. Remember, time and space mix - space becomes time and time becomes space.===================================
Look at the following animation to see this:
You should see that the transit time of red spots are different in different directions, despite the fact that the rate of red spots is equal(same) in both directions. The first expression allege that these times are identical.
Let solve one a school's puzzle:
1. Two travelers do walking on the road with equal speed () in one direction at a distance () from each other.
2. Between them runs a dog (speed of it ).
QUESTION: How much time a dog runs forward, and how many - back?
ANSWER: and
But Einstein, Lorentz, Minkowski and others (who entrust to them) say that time will be the same. So is was alleged by the first expression.
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Time dilation can not be responsible for (to cause) two the physical phenomena simultaneously: acceleration time and deceleration time. Must be one thing.This is still gibberish.What do you mean by "Time is not different"?[math] x^2-(ct)^2=(x')^2-(ct')^2=0 [/math]
[math] x^2-(ct)^2=0 [/math]
[math]t_1=x/c[/math]
[math]t_2=-x/(-c)=x/c[/math]
Time is not different
[math] x'^2-(ct')^2=0 [/math]
[math]t_1'=x'/c[/math]
[math]t_2'=-x'/(-c)=x'/c[/math]
Time is not different
[math] (x'-vt')^2-(ct')^2=0 [/math]
[math]t_1'=x'/(c-v)[/math]
[math]t_2'=-x'/(-c-v)=x'/(c+v)[/math]
Time is different
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To unambiguously only.This is gibberish.
Look:Please quote the precise part of your post where you show that the equation is incorrect. I don't want an assertion; I want a specific proof.Time must be diferent.
[math] x^2-(ct)^2=(x')^2-(ct')^2=0 [/math] - Time is not diferent. It's error.
[math] x^2-(ct)^2=(x'-vt')^2-(ct')^2=0 [/math] - Time is diferent:
[math]t_1'=x'/(c-v)[/math]
[math]t_2'=x'/(c+v)[/math]
It's correct.
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???No, you never have.
Yes. But reality has it and reality has not double time dilation.First, under special relativity we don't see any two frames where one accelerates time relative to the other and the other slows down.
Similar ambiguity is impossible.Second, why does one exclude the other?
#140You have yet to demonstrate this.0 -
I demonstrated to you the inadmissibility of the simultaneous slowing of time.
You have not explained why this is necessary.Slowing down time of your buddy is the reason that he sees the acceleration of your time.If one sees the acceleration, while the second sees a slowdown, and this is logical, then other option (two slowing )can not be logical.
Again, relativity does not violate causality. Relativity states that if event A causes event B, then event B must be in the future light-cone of event A. If that is true, then no change of frame can cause event B to happen before event A, so causality is not violated.The time delay of your buddy can not is the cause of the acceleration.If the first case does not violate the principle of causality, the second must to do it.
This x²-(ct)²=(x')²-(ct')²=0 (light-cone) is not correct.
This x²-(ct)²=(x'-vt')²-(ct')²=0 is correct.
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Slowing down time of your buddy is the reason that he sees the acceleration of your time.And why is ambiguity a problem? As long as cause always precedes effect - which is true in relativity - there is no problem with ambiguity.The time delay of your buddy can not is the cause of the acceleration.
If the first case does not violate the principle of causality, the second must to do it.
The lie can be called by different names, but this name can not convert it to truth.That is the reason it is called "The relativity of simultaneity".0 -
If time of your companion will slow, then he will be see the acceleration of your time. I am sure that you argue with that you will not.
Alternatively: if your partner sees and slowing down your time - is impossible. Otherwise we would have the ambiguity.
Reasons time dilation does not matter.
Relativistic effect of delay could be a reason for it, but relativism can not slow down time for both.
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My programs can not interpret your message.
Your sentences are too long.
Too many words of one sentence, so translation is difficult.
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The mathematical expression:
[math]x^2-(ct)^2=(x')^2-(ct')^2=0[/math]
is not a consequence of the universality of the speed of light.
So the result is the following expression:
[math]x^2-(ct)^2=(x'-vt')^2-(ct')^2=0[/math]
Look at the following animation to see this:
You should see that the transit time of red spots are different in different directions, despite the fact that the rate of red spots is equal(same) in both directions. The first expression allege that these times are identical.
Let solve one a school's puzzle:
1. Two travelers do walking on the road with equal speed ([math]v[/math]) in one direction at a distance ([math]L[/math]) from each other.
2. Between them runs a dog (speed of it [math]c[/math]).
QUESTION: How much time a dog runs forward, and how many - back?
ANSWER: [math]T_1=L/(c+v)[/math] and [math]T_2=L/(c-v)[/math]
But Einstein, Lorentz, Minkowski and others (who entrust to them) say that time will be the same. So is was alleged by the first expression.
==============================================================
Let talk about an electron-neutrino and an electron-antineutrino.
The latter occurs in a pair with a positron. (A first - in a pair with an electron.)
But those neutrinos (and antineutrinos) are not some separate particles.
When paired with an electron positron born. And nothing else. What is called the electron neutrino is a positron, whose rate is greater than the speed of light. Well, the electronic antineutrino is - an electron whose velocity is greater than the speed of light.
The mass of both are 0.5 MeV (0.28 eV obtained by SRT-formulas, when the mass of the speed dependent). But mass no depend on a speed today.
These neutrinos and antineutrinos are produced as a result of common (cascading) decay, when an particle decays into a pair of electron + positron. In some cases, the electron flies in the same direction, which gave birth to it. In this case, the electron (speed of which > c) is called the electron antineutrino.
If the positron flew forward (the electron - back) then the positron called by electron neutrino.
In those cases where the electron and positron fly away (to broadside direction), and result of their speed does not exceed the speed of light, we are witnessing the birth of an pair of electron+positron.
It would be strange to call the bus, which moves in some other way (not, as we call the bus, which stoped). But physics have it. We called neutrino all elementary particles (whose velocity is greater than the speed of light).
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This means that the visual effects (arising due to the special properties of EMF) do not have direct coupling to a transformation of coordinates (and in general - to the coordinates). In any case: properties of light have coupling to a coordinates transformation to the same extent that the sound to coupling to it.
This means nothing.Visual effects and sound effects have approximately equal ratio to the real coordinates.
Because of the finite speed of light we see distant stars and galaxies as they were millions of years ago. Everyone knows that stars and galaxies are now in a different place and differently look.What physically do you mean by "visual effects"?This is an example of visual coordinates and visual effects.
the property mentioned???That doesn't say anything about why transformation matrices must have the property mentioned.0 -
BBC news
22 September 2011 Last updated at 17:28 GMT
Speed-of-light experiments give baffling result at Cern
hyperz, my thanks to you for this news.
Visual effects and sound effects have approximately equal ratio to the real coordinates.What is a "visual effect"? What does that mean physically?
The transformation matrices have meaning for real coordinates only.Then what is special about transformation matrices that it should be true for them?0 -
Even if such a rule exists, then to me about him is not known.I'm asking you to make a specific answer, yes or no.If you have a matrix A - any matrix A - and you know that A0,0 > 1, does that mean that
A-10,0 must be less than 1?
I admit that this rule can applies to a particular class of matrices.
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But that simply isn't true under Galilean transformations. The speed of light changes under Galilean transformations. Which means that it is observer-dependent - it is not the same for different observers. Which makes it non-absolute.
Galilean transformations for real coordinates only. (Real coordinates to real coordinates.)That result is there in Galilean relativity and special relativity already. It is a trivial statement. I'm asking you to make a specific statement about your theory.Relativism is visual effect only.
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Master Theory
in Speculations
Posted · Edited by hypervalent_iodine
Fixed LaTex codes
Master Theory (MT) is a theory of relativistic.
MT satisfies the same conditions, which satisfies Einstein's Special Theory of Relativity (SRT).
Experimental evidence, confirmative SRT, confirm MT.
The difference in interpretation and in a results of experiments that are not public.
For example: in scientific literature there is no experimental confirmation of a formulas:
[math]E=mc^2/\sqrt{1-v^2/c^2}[/math]
[math]p=mv/\sqrt{1-v^2/c^2}[/math]
In Master Theory these formulas is stale.
In MT time is absolute therefore heve not "Twin Paradox".
In MT light speed, acceleration and mass is absolute (do not depend on the speed and are the same in all Inertial Frame).
Inertial Frame (IF) are equal in rights.
You can ask me: Einstein's task has non-unique solution?
My answer: YES!
How can this be?
My answer: Please note that a transverse coordinates ([math]y[/math] and [math]z[/math]) of Lorentz Transformations are absolute (whereas Einstein asserted that in his theory of everything is relative).
Einstein (had no no reason for it) gave the absoluteness for a transverse coordinates, but not for - time.
I exempt the transverse coordinates ([math]y[/math] and [math]z[/math]) from Einstein's absoluteness.
I to do free from Einstein's absoluteness the transverse coordinates (I set relative it, I set dependence on velocity for it).
So I got a free parameter.
For each value of this parameter, you can build a individual theory of relativity, which will exist as scientific theory on equal terms with SRT.
Moreover, because the transverse scale also depends on the speed (diminishing) - it is possible to solve the paradox of Ehrenfest (the paradox of a rotating disk).
Thus, Einstein's task has an infinite number of possible solutions, and SRT - only one solution of this infinite set.
Among this infinite number of solutions I've found one, in which time is absolute.
I call this theory: "Master Theory".
Only this theory is correct because it have not SRT's paradoxes.
So: Master Theory have absolutely time, and this difference has profound implications. (For example: in Master Theory are absent "Twin Paradox" and "Ehrenfest's Paradox".)
Master Theory
Let us consider the light-clock with a pair of vertical mirrors (one on the left, the other - right) and photon between them:
[math]L[/math] - the distance between the mirrors.
Time's cycle:
[math]T=L/c+L/c=2L/c[/math]
Suppose that we (the observer) has a motion with velocity [math]v[/math].
Îscillogram of this motion:
Speed of light in all cases is well-known-constant.
Hence the transit time of a photon from mirror to mirror in different directions will be different.
This is because: moving in one direction - the photon (in the view of the observer) meet-moving to the mirror (flight time is less).
In the other direction - in pursuit of the mirror (flight time is major):
[math]T=L/(c+v)+L/(c-v)\neq 2L/c[/math]
Acceptably are three variants:
1. Happened a time-dilation [math]T'\neq T[/math]
2. Happened a curtailment the visual of the longitudinal scale [math]L'\neq L[/math] (Master Theory);
3. Happened all (both of the above) (SRT).
We consider the second variant (corresponding Master Theory):
[math]T=L'/(c+v)+L'/(c-v)=2L/c[/math]
The longitudinal scale of the rate is (for the second variant) calculated as follows:
[math]L'/L=1-v^2/c^2[/math]
This SRT's formula looked so: [math]L'/L=\sqrt{1-v^2/c^2}[/math]
We proceed to calculate the cross-scale.
For this we consider new light-clock, which have a pair of horizontal mirrors (one - from the bottom, the other - from the top):
Time's cycle: [math]T=2H/c[/math]
Suppose that we (the observer) has a motion with velocity [math]v[/math].
The trajectory of photon will change into sawtooth and elongated:
Photon has a fixed velocity and can not travel long distances over the same time.
We proceed to calculate the cross-scale.
For this we consider new light-clock, which have a pair of horizontal mirrors (one - from the bottom, the other - from the top):
Time's cycle: [math]T=2H/c[/math]
Suppose that we (the observer) has a motion with velocity [math]v[/math].
The trajectory of photon will change into sawtooth and elongated:
Photon has a fixed velocity and can not travel long distances over the same time.