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mathsgiup

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Posts posted by mathsgiup

  1. This is a pure combinatorial question:

     

    To take it into the real world let's discuss Buckminsterfullerene:

     

    http://en.wikipedia.org/wiki/Buckminsterfullerene

     

     

     

    http://en.wikipedia.org/wiki/Truncated_icosahedron

     

    See that:

     

    Buckminsterfullerene has 60 atoms and 90 edges, edges are equivalent to connections, yes?

     

    Now add 1 atom in the middle, there is a line or 'connection from each of the 60 atoms to this new atom:

     

    Now we have, 61 atoms and 150 connections, see?

     

    Combinatorially, brain connections is a massively huge number, easily more than atoms in the universe.

     

    Let's say the maximum number of connections n atoms can have is X, as a function, we can represent this as f(n)=X

     

    Now add 1 more atom:

     

    This new atom can connect to maximally n other atoms so:

     

    f(n+1) = X + n

     

    but

     

    f(n)=X therefore

     

    f(n+1)= f(n) + n

     

    but then, f(n) = f(n-1) + (n-1)

     

    so we have

     

    f(n+1)= f(n)+n = [ f(n-1) + n-1 ] + n = f(n-1) + 2n -1

     

    now

     

    f(1)=0 - dot

    f(2)=1 - line

    f(3)=3 - triangle

    f(4)=6 - cross hatched square or tetrahedron

     

    Dimensionality also has an effect.

     

    In 2d you will see that f(n)= Summation (Binomial n,k) for k=1 to k=n-1.

     

    binomial tree:

    1

    11

    121

    1331

    14641

     

    f(4) = 6 =

    f(5)=1+3+3+1=8 - cross hatched pentagon

     

    however 5 points in 3 dimensions, what happens,

     

    .......work it out, it will take you a few hours :)

     

    OR

     

    type in

     

    maximum number of edges and vertices in 3 dimensions

     

    into google

     

    Thanks,

    D

     

     

     

     

    f()

    f()

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