sloppycoder
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Hello there, and hi from me! I've just joined to find out about this particular issue but hope to also be an active participant in this forum!
I've been measuring current in a circuit with an improvised ammeter. This consists of a known good Digital Volt meter connected across a 10 Ohm 7 watt resistor. This (shunt) resistor is then placed in series with the circuit (IE circuit is broken until resistor is connected)
Two questions really;
1) Is that the correct physical layout for this type of test?
2) Is my maths right.......
Measured 0.0052v across resistor. By Ohms law i should devide this by the resistor value to get the current so 0.0052/10 = 0.00052 amps.
Many thanks, all help appreciated.
Alf
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Improvised ammeter usage question...
in Homework Help
Posted
Thanks very much for the replies That has put my mind at ease!
What i was attempting to measure was the idle drain current on the battery installed in my van. I tried measuring the resistance between the battery terminals (with one disconnected from the battery) and that was incredibly high something like 10,000m Ohm? Battery voltage is ~ 13.5v
I might try again with a higher value resistor for a more accurate reading but i think i can probably safely rule out a battery drain as the source of my flat battery problems.
Thanks again, will return with more conundrums another time.
Alf