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Mad Scientist

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Posts posted by Mad Scientist

  1. For a glacial study i am undertaking i want to prove a hypothesis that a Ribbon lake once occupied a valley because it was dammed at the end by morraine. For this i will be using an ogre too dig down into the soil on the valley floor. Does anyone no what sort of things i should be looking for in the soil that will prove my Hypothesis. Any info would be greatly appreciated.

  2. Hi, could someone please help me with the question below :

     

    Crystals of hydrated sodium carbonate left exposed to the atmosphere gradually lose some of their water of crystallisation. The formula of the crystals may be given by Na(2)CO(3).xH2O where x has a numerical value between 0 and 10. 16 grams of the crystals were dissolved in water and made upto 250cm3 in a standard flask. To determine the value of x, 25cm3 of the sodium carbonate solution were titrated with 1.0M hydrochloric acid. 15cm3 of the acid was required for neutralisation.

     

    (1) Calculate the mass of sodium carbonate (Na(2) CO(3)) in 16 grams of the crystals.

    (2) Calculate the value of x in the formula Na(2)CO(3).xH2O

     

    Any help would be greatly appreciated. Thanks,

    Mad Scientist

  3. Sice P=IV then the power would change would it not because the current and the voltage would be changing. This is how i would do that question -

     

    In secondary -

     

    P=IV

    1600=200*V

    V=?

     

    So using equation ?/100 = I/200

     

    then you would cross multiply to work out I

     

    Note - the ? is the answer for the voltage which can be found out using the P=IV equation above. The site does not allow you to give answers only help so try doing it yourself.

  4. Well its a ratio. So The number of coils in the secondary divided by the primary will give a constant. Say the number of coils in the secondary was 300 and the number of coils in the primary was 150. The the constant would be 2. If you know the current in the primary you can then multiply it by two to get the current in the secondary or if you have it for the secondary you can divide it by two to get the current in the primary. Note the ratio does not work for the power.

  5. If the reactants react to give an exothermic reaction the the enthalpy change will be a minus ie heat is given out. For the reverse reaction the enthalpy change will have to be positive meaning that energy is taken in making the reverse reaction endothermic. I have never seen a case of both the forward and the reverse reactions eing both exothermic or endothermic.

  6. This is one of these don't try this at home experiments but if your in a lab try pouring a test tube full of water over oil thats on fire. Its well fun. If you've never seen it you get a massive fireball due to the rapid exspansion of air inside the oil. Good times.:D

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