dorcus

Hello,

That is slightly confusing.

So what you are suggesting is that I divide x^10 by x^3 3 times, while dividing x^5 one time. But are you allowed to do that?

I would have thought that you would need to divide x^10 and x^5 the same amount of times. Is there a property that perhaps I have not heard of that allows you to do that?

Thanks!

Hello,

I am sorry for not clarifying properly. What I meant that doing the quadratic equation would not be practical as taking the answer to the 10th power and adding it to the 5th power would require extensive calculation (The problems are designed to have "simple" calculations).

DH,

multiplying each side by x-1 would give:

x^3-1 = 0 or, x^3 = 1

which yields, x = cube root of 1, which is 1.

But I don't understand how that would work.

1^5 + 1^10 +3 = 5

When the answer is 2.

Am I doing something wrong?

Thanks.

Hello,

I am studying for examinations and encountered a problem I do not know how to solve:

Let w (omega) be a solution of the equation x^2 + x + 1 = 0

Then w^10 + w^5 + 3 = ?

I first replaced x with w (omega)

which yields

w^2 + w + 1 = 0

What I actually tried to do is solve the actual value of "w" using the quadratic equation. However, when I plug this into the 2nd equation, this yields "3", when the answer is 2.

Also, no calculators are allowed on the exam, so I can't be using the quadratic equation.

Any help is appreciated.

Thanks.

Hi,

My teacher and I were discussing my research project: A study of Potential Monogamy Behavior in the Family Dendrobatidae, and the conversation resulted in the my teacher telling me that I'd need to use some advanced statisticals formulas to determine what percentage of the females are required to repetitively choose the same male frog in order for it to be classified as "potential monogamous behavior". Any ideas? (there are 6 frogs. 2 females and 4 males, but everytime, only two males are introduced to a female at any given time.)

Help is greatly appreciated!

Thanks in advanced!

can someone help me solve these two equations (and please explain)?

log9 (q) = log12 (p) = log18 (q + p)

what is q and what is p?

and....

sinA + sinB = (square root 2) over 2

cosA + cosB = (square root 6) over 2

sin(A + B) = ?

Thanks in advanced!

thanks guys

budellwraagh, that's exactly what i was talking about

I was just wondering if Barium Hydroxide + Ammonium Chloride would be a dangerous endothermic reaction.

well, technically if we were to inhabit another place, it would NOT be the moon; because the moon isn't that much farther to the Sun than Earth is. So we would still die out....

uh huh... i can't think of anything either.. anybody know of anything else?

nice pics!!! those snakes look so cool! I've been to Taiwan, but i rarely see snakes there... Perhaps i'll go to Guam sometime...

Well, i think i addition to the lizard's quick speed, it also had something to do with his light weight. We humans are too heavy... Well, think about it.... A cheetah is probably faster than the lizard. But can cheetahs "walk" on water? I don't really think so...

I would also like to add that Electromagnetic Radiation with a wavelength between 400 nm and 700 nm can be detected by the naked eye, and is percieved as visible light.