Fiona G
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So would it be: 10.5kN * sin(60) + ( - (8.17kN * sin (50) ) = 0 I am not too sure, however this is my best guess on how to calculate the verticals.
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So I got as far as: 8.17kN * cos (50) = 10.5kN * cos (60) 8170 * cos (50) = 10500n * cos (60) 5251.57n + 5250n = weight 10501.57n but I’m fairly confident that’s wrong…
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Hi, thanks for your reply. I’m in Scotland, and school started for us on 16th August. I understand the laws of static equilibrium, and I’m also familiar with FBDs. Yes, you’re right. I meant questions. My apologies.
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Hi, yes I do understand Pythagoras I’m just not sure how I should apply it to the second question?
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Hi, I am 15yrs old and I have just started taking engineering science. I am struggling to understand how to solve these equations and I was wondering if someone could help explain them in really simple terms? Please note, I am NOT asking for the answers; I want to learn how to do these myself, so I would really love a breakdown of what to do and why we’re doing it. Thanks in advance.
