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George Dowell

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Posts posted by George Dowell

  1. 3 minutes ago, swansont said:

    If by “high energy mode” you mean creating other massive particles, it’s dictated by the mass of the particles you create.

    No sir,  sorry I'm not clear, it is only e-e+ is what I'm asking about.

    Now I see you said "in colliders" in your answer. That is the high energy mode I'm referring to, but want to know where between Thermalized and a Collider does e-e+. For example at 542 KE, it is not allowed. Before it can, either Bremsstrahlung or collisions happen, either to the positron alone or to a positron-electron atom (positronium), until the pair are at rest, then annihilation happens with the common dual but opposed 511 keV from the pair's rest energy.

    Outside of a collider environment, are there commonly known e-p annihilation's that produce, say 1000 keV pairs photons, or anything besides 511 keV pairs?

    Thank you.

    Geo

  2. 11 minutes ago, swansont said:

    If that were the case, you would not get other results from e- e+ collisions in colliders. But we do.

    During. 

    Thanks. Could you point out a reference where these other energies are mentioned please. And if possible, where does the low energy ("thermalized"  or "at rest" they"are calling it) stop and the high energy mode become possible? I'm only concerned with electrons and positrons, not the other positron/particle annihilations.

    Thanks for your time.

     

    Geo

     

  3. On 8/2/2019 at 12:32 PM, Amazing Random said:

    Try to think sound as waves and each wave is a circle . Ok let's take a source of sound or sound waves . The source emmits sound waves at a certain frequency . Ok? When the source is immobile the receiver receives the sound waves with the same frequency emmited from the source.When the source is moving however the distance between two waves changes (due to the moving source) so since the distance between the waves is increased the next wave takes more time to be arrived so the frequency received by the receiver is changed.

    If I may add a practical example to verify the quoted above:

    As a Ham Radio operator, one of the many aspects that fascinated me was E.M.E.- That is a radio path which originates on the earth (me) travels to the moon, is reflected, a portion of that comes back to the earth. This happens on 144 MHz.

    When I listed to my own radio signal coming back, 2.7 +/- seconds later, it is on a different frequency at my location than the original frequency. The difference frequency is constantly changing due to the constant orbital motion, and will be above or below the transmitted frequency depending is the moon is advancing or receding relative to my position. We use this path to 2-way communicate with other radio stations scattered all over the world. This is Doppler shift and shows both + and - , or in light would be blue and red shift.

    The other earthly example is Police Speed Radar- they used continuous transmission 10 GHz when I worked on them, the signal hit a car and bounced back to the duplex antenna at the transmitter, where a tiny portion of the transmitting signal was mixed with the received signal, yielding a difference frequency equal to the Doppler shift caused by the vehicles velocity. This was in the audio range and could be accurately counted, the frequency being displayed in MPH for the operator to see.

    Both these are relativistic examples, and I believe the formulas  some mentors mentioned were the same ones we applied to radio frequency Doppler shift.

     

    Geo>K0FF

    K0EME

  4. On 8/18/2019 at 2:54 PM, swansont said:

    The annihilation releases energy, so there is no threshold - it does not need to be “forced” 

    If there is KE, the photons will have more than 511 keV, or (with sufficient energy) you can produce other, heavier particles

     

    It's my understanding the electron-positron annihilation can only take place when both particles have no remaining kinetic energy, and my experiments bear that out - always two 180 degree opposed 511 keV photons. When positrons are created they do have kinetic energy, but before annihilation they loose it through collisions or radiative effects.

    What I'm trying to figure out and have no direct knowledge of, is the high energy mode (collider- like LEP), when they are forced together with very high kinetic energy naturally that energy is used up, transformed into particles and waves, conserving the original energy. Does this happen, before, during or after annihilation?

    Thanks

    Geo

     

     

  5. Electron-Positron Annihilation, low energy vs high energy mode- do both end in 511 keV Annihilation?

    Normal room temperature electron-positron annihilation is a well documented process, used in industrial, medical and metroloogy fields, among others.

     

    There are two modes of e-p annihilation, the room temperature or so-called low energy model, and the high energy model (think storage Rings, accelerators, colliders).

     

    In the latter category, do the e-p particles annihilate and produce 511 keV opposed photons like in a normal annihilation, or is there a threshold where e=p annihilation can be forced by kinetic energy alone?

     

    Citations/ references if you please, not personal opinions, I need to prove this to someone, one way or the other.

     

    Thank you for your time.

     

    George Dowell

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