student_lfcs
-
Posts
4 -
Joined
-
Last visited
Content Type
Profiles
Forums
Events
Posts posted by student_lfcs
-
-
-
Ok. Please see if I am right this time:
Total mass =18,000 kg
Net force exerted= 40000 - 5000 = 35000
Accelration: 35000 / 18000 = 35 / 18 = 1.95 m/s^2
force exerted by wagon 1 on wagon 2: Accelration x Mass
Mass in this case = 4 x 2000 = 8000 kg; Accelration is same i.e. 1.95 m/s^2
So F = 8000 x 1.95 = 15555 N
0 -
Ques: An 8000 kg engine pulls the train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 newton and the track offers a frictional force of 5000 newtons then calculate the force of wagon 1 on wagon 2.
Ans ( I tried) : Total weight =18,000 kg
Net force exerted= 40000 - 5000 = 35000
Accelration: 35000 / 18000 = 35 / 18 = 3.5 m/s^2
0
Images formed by plane mirrors
in Homework Help
Posted
Please reply