smart person
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How much Power do I need to levitate 1 kg?
in Speculations
Posted · Edited by smart person
missed clarifying a step (gpe = mgh)
we can just use the gravitational potential energy formula to work out how much kinetic energy 1kg would have after falling for 1 second, to give us the theoretical minimum power required to generate an equal and opposite reaction force against gravity.
first find height after one second of falling using integration: v=9.8t, => d=4.9t^2, d=4.9*1^2=4.9m.
work out GPE based on height: GPE = mgΔh, GPE = 1kg * 9.8 * 4.9 = 48.02J, P = 48.02J/s = 48.02W.
looks like you were correct?